How to Calculate % improvement in Mozrank and Domain Authority
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I understand the concept that mozrank and Domain Authority are measured on a logarithmic scale . http://www.seomoz.org/learn-seo/mozrank
I'm trying to determine the percentage improvement in the Logrithmic value. For example
Original Domain Authority 60
Original Mozrank 5
End Domain Authority 63
End Mozrank 6.
So 5% change in DA and 20% change in MozRank. How do we convert these numbers to the real logrithmic change?
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He's giving you a nonsense number, because SEOMoz won't reveal the true scale, so use whatever logarithmic scale you want.
ie. an indeterminate amount
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Super interesting question!
First, let me put out a disclaimer that metrics like Domain Authority are comparative metrics that change from index to index. This means that it's best to use these numbers to compare yourself to the competition, but not to your own previous metrics as the base calculations can change. DA measures relative strength - so it's completely possible to improve 10% by raw numbers, but if your competition improved 10% as well, your relative DA really didn't change. For this reason we caution against folks measuring DA over time, and instead using it as indicator of ranking potential in real time against other competitors.
With that out of the way, last time I checked, MozRank was calculated on an algorithmic base scale of around 8.5. (Sorry, I can't be more specific - but that's part of the secret sauce. Heck, I don't even know the exact numbers.
With this knowledge, you can use a typical base calculator to figure relative strength. For example, a Mozrank of 5 on an 8.5 log scale calculates to 44370.531 um... raw MozRank points. Using the same calculations we find a MozRank 6 equals 377149.516 raw points, or 8.5x the original.
You can do similar calculations to determine the logarithmic change of DA, but keep in mind the disclaimer above and remember that since we can't reveal the exact scale, your calculations will be estimations, at best.
Hope this helps!
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Sorry can you elaborate?
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Multiply the original MozRank by a buck two eighty.
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